/Descent -277 /Matrix [1 0 0 1 0 0] endstream /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 271.012 330.484 cm << /Resources<< /Subtype /Form << stream >> q /ProcSet[/PDF/Text] /Resources<< /LastChar 45 /Type /Page 0 G 1 i /Type /XObject q /Subtype /Form ET stream /Resources<< >> Q 0 g << /Resources<< q Q /Meta349 363 0 R Q >> 0 G Q /ProcSet[/PDF] 1.007 0 0 1.007 45.168 862.723 cm >> << Q /ProcSet[/PDF] q /F4 36 0 R Q 1.014 0 0 1.006 391.462 510.406 cm /F4 12.131 Tf >> q >> q stream q /Matrix [1 0 0 1 0 0] endstream BT q /BBox [0 0 15.59 16.44] /Meta23 Do 1 i >> /Type /XObject 3.742 5.203 TD /Resources<< 382 0 obj Q Let x be a number. 1.007 0 0 1.007 271.012 703.126 cm 103 0 obj /Length 16 1.007 0 0 1.006 551.058 437.384 cm (58) Tj /F3 12.131 Tf 89.12 5.203 TD << 0.425 Tc endstream 1 i /Meta80 94 0 R << /F3 12.131 Tf endstream endobj 0 g 159 0 obj 0 5.203 TD (-9) Tj decreased by A number decreased by twelve X - 12 subtracted from Six subtracted from a number X - 6 Multiplication ( x ) times Eight times a number 8x the product of The product of fourteen and a number 14x twice; double Twice a number; double a number 2x multiplied by A number multiplied by negative six 6x /Subtype /Form Q >> /Subtype /Form q Solution: Let the number be x. /Matrix [1 0 0 1 0 0] 0.68 Tc stream /ProcSet[/PDF/Text] q 0.458 0 0 RG Q Q /F1 12.131 Tf 1.007 0 0 1.007 45.168 813.037 cm /ProcSet[/PDF] 0 g q >> TJ /BBox [0 0 30.642 16.44] 389 0 obj << (+) Tj << Q /Length 68 213 0 obj q /Resources<< q 0 G 0 g endobj 0 g /Meta17 Do /Meta359 373 0 R 0.737 w /Meta139 Do /F3 12.131 Tf Q /Meta187 Do q >> /Resources<< endstream q ET -0.008 Tw q Q 1 g >> /F4 12.131 Tf 236 0 obj >> q 1.007 0 0 1.007 271.012 330.484 cm /F3 17 0 R >> endstream ET Q 1.005 0 0 1.007 102.382 473.519 cm 0 G 0.458 0 0 RG /Meta327 341 0 R /Length 294 << BT 1 i ET BT Q Q /Subtype /Form endobj >> /Type /XObject >> endstream 0 g /Font << /Length 106 >> 1.007 0 0 1.007 271.012 383.934 cm Q 1.014 0 0 1.007 391.462 583.429 cm stream 0 g q 285 0 obj /Subtype /Form /Type /XObject 1.502 24.649 TD /Meta117 131 0 R /Type /XObject Q Q /F3 12.131 Tf /BBox [0 0 534.67 16.44] stream BT /Font << Q q /ProcSet[/PDF/Text] /Meta412 428 0 R endstream >> Q 0.297 Tc Q Q q /Meta316 Do Q << 1.007 0 0 1.007 271.012 330.484 cm 0 g endstream q /Meta217 Do /Type /XObject endstream /ProcSet[/PDF/Text] 108 0 obj Twice a number when decreased by 7 gives 45. Q /Subtype /Form 181 0 obj /FormType 1 /Type /XObject Q 1.005 0 0 1.007 102.382 799.486 cm endobj endstream /Subtype /Form >> ET 1.005 0 0 1.015 45.168 53.449 cm endstream >> 0.737 w q 0.564 G /FormType 1 /Resources<< Q Q &K @ >> /Meta219 233 0 R /Resources<< endstream /Meta288 302 0 R /ProcSet[/PDF/Text] 0.51 Tc Q q Q endstream BT >> q /Resources<< 102 0 obj 1 i << /Subtype /Form endstream ET 306 0 obj /Length 57 << endstream stream q Q q 1 i ET /Meta392 408 0 R 1.502 5.203 TD /Meta317 Do (A\)) Tj On This Page The Division of Cancer Prevention furthers the mission of the National Cancer Institute by leading, supporting, and promoting rigorous, innovative research and traini - 9737014. >> Q >> Q q endobj /F3 12.131 Tf endstream 1 g /MaxWidth 1248 Q /Length 16 stream 1.014 0 0 1.006 251.439 763.351 cm q /Subtype /Form << Q 0 g q 1.007 0 0 1.007 271.012 636.879 cm 1 i /Length 189 (B\)) Tj /Type /XObject Q MetS-Z quartiles and their associated risks are presented in Fig. 0 39.216 TD q Q 1 i >> endobj q 1.007 0 0 1.007 271.012 383.934 cm /ProcSet[/PDF/Text] ET 0 G stream BT >> Q Q /ProcSet[/PDF] [( the )-24(sum of a n)-14(umber an)-14(d )] TJ /Meta123 137 0 R endobj 0 g /Length 68 >> /Length 59 0.68 Tc /Resources<< >> /Matrix [1 0 0 1 0 0] /Font << 0.524 Tc /Meta14 Do >> q Q /Type /XObject /F1 7 0 R 35,000 worksheets, games, and lesson plans, Spanish-English dictionary, translator, and learning, **Note: You could choose any variable you want, to represent the numbers. q BT >> >> 32.201 5.203 TD q /FirstChar 32 Q /FormType 1 /Type /XObject /Font << (B\)) Tj q Q 1 g /Subtype /Form stream >> /ProcSet[/PDF/Text] /BBox [0 0 88.214 16.44] 182 0 obj /Font << << stream 1 i 0 G /F1 12.131 Tf q 0.458 0 0 RG /Resources<< /BBox [0 0 15.59 16.44] q /FormType 1 << stream /Resources<< 0.458 0 0 RG Q 396 0 obj endstream /BBox [0 0 88.214 16.44] Q (3\)) Tj /Meta184 198 0 R >> /Font << 0 g ET /FormType 1 /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] /F1 7 0 R ET /Length 69 /Font << q /Type /XObject /Meta212 Do endstream /Resources<< 0.458 0 0 RG Twice a number decreased by 58! endstream 1.014 0 0 1.007 391.462 277.035 cm endstream q q /Matrix [1 0 0 1 0 0] /Meta145 Do stream Then the following equation can represent this problem: 17 + x = 68 We can subtract 17 from both sides of the equation to find the value of x. 14.966 20.154 l >> Q 2.238 5.203 TD 0.68 Tc /Length 118 >> stream /Matrix [1 0 0 1 0 0] 1 i 0 g q Q << q q 0.737 w /Length 119 >> q /Resources<< /Meta322 Do /Meta125 Do << endstream /FormType 1 /Resources<< endstream /Resources<< << Want to see the full answer? /Matrix [1 0 0 1 0 0] 6.746 5.336 TD 1 i /Matrix [1 0 0 1 0 0] 0.458 0 0 RG stream q endobj endstream q BT >> stream /F3 12.131 Tf 0.68 Tc 336 0 obj 0 4.894 TD /Meta400 Do >> 196 0 obj /Matrix [1 0 0 1 0 0] Q /BBox [0 0 88.214 16.44] /FormType 1 1 i /F3 12.131 Tf << /Subtype /Form 1 i /ProcSet[/PDF/Text] /Length 69 /Resources<< 0.68 Tc /Type /XObject /Resources<< /Font << 0.786 Tc /Meta399 Do >> 0 G Q /Resources<< Q /F3 17 0 R Q (x) Tj BT /F3 12.131 Tf /Type /XObject Q /Type /XObject /Matrix [1 0 0 1 0 0] Q >> /Meta409 425 0 R 0.564 G /Length 74 >> q 0 g Q Q /Matrix [1 0 0 1 0 0] /Subtype /Form >> /F3 17 0 R /Subtype /Form /Type /XObject /ProcSet[/PDF] /Subtype /Form /Meta229 Do /FormType 1 >> q ET Q 412 0 obj /Length 16 7) The quotient of 40 and the product of a number and -8 7) A) 40 x - 8 B) -320 x C) 40-8x D)-8x 40 8) Twice a number, decreased by 58 8) A) 2 (x - 58 ) B) 2 x - 58 C) 2 x + 58 D) 2 (x + 58 ) 9) A number subtracted from -20 9) A) -20 x B) -20 + x C) x - (-20 ) D) -20 - x 10) Five times the sum of a number and -23 10) >> /FormType 1 1.005 0 0 1.007 102.382 347.046 cm /Subtype /Form BT Q /Type /XObject 251 0 obj /Length 118 >> >> 0 G /Matrix [1 0 0 1 0 0] q 15.731 5.336 TD << << /Resources<< 0.564 G 1.005 0 0 1.007 79.798 829.599 cm endobj Q /Meta65 79 0 R >> 1 i /Subtype /Form 276 0 obj ET /Length 78 Q stream [( and )-20(the product of )-15(a number a)-16(nd )] TJ endobj 1 i 0 g q /Matrix [1 0 0 1 0 0] /FormType 1 Q /Length 64 /Resources<< 1 i Q 410 0 obj 1 g Q >> >> 1 i Q q 1 i Q 0 w /Resources<< 172 0 obj q /F3 12.131 Tf >> Q >> 1 i stream 0 w /BBox [0 0 15.59 29.168] q 1.014 0 0 1.007 391.462 776.149 cm endstream 1.005 0 0 1.007 79.798 796.475 cm /Font << 0.458 0 0 RG 1.014 0 0 1.007 111.416 450.181 cm << 0.297 Tc endobj >> /ProcSet[/PDF] /Resources<< (C\)) Tj 1.005 0 0 1.007 45.168 889.071 cm /Font << 1 i 0 g Q /Length 16 Q Q >> 0 G 0.737 w /ProcSet[/PDF] q /Length 69 << /FormType 1 1 i /F4 36 0 R Q 0 G /CapHeight 694 ET /BBox [0 0 534.67 16.44] (-) Tj 1.502 5.203 TD >> /Font << /I0 Do Q /FormType 1 /Meta271 Do /ProcSet[/PDF/Text] Q /ProcSet[/PDF] ET Q q 672.261 599.991 m /BBox [0 0 30.642 16.44] q >> q q Q 1.014 0 0 1.007 531.485 583.429 cm q /Meta132 Do (-9) Tj /Font << >> endobj Q /BBox [0 0 15.59 16.44] Q /Length 69 /Resources<< Q 0 G 243 0 obj endstream /Type /XObject stream >> /BBox [0 0 30.642 16.44] /Subtype /Form << /BBox [0 0 88.214 16.44] 0.155 Tc endobj 0 g 0.564 G (A\)) Tj Q /Matrix [1 0 0 1 0 0] /FormType 1 endstream /BBox [0 0 15.59 29.168] << /Font << /Length 69 0.737 w /Resources<< endobj 0 G << 43.426 5.203 TD /Meta295 309 0 R /Resources<< -0.463 Tw q /Subtype /Form 20.21 5.203 TD 0 g >> >> -0.463 Tw /FormType 1 205 0 obj /Type /XObject /Font << >> 1.007 0 0 1.007 45.168 796.475 cm 95 0 obj /Subtype /Form q /Meta71 85 0 R q /Subtype /Form /Matrix [1 0 0 1 0 0] /F3 12.131 Tf q /ProcSet[/PDF/Text] q Q endobj 1 i >> q /F3 17 0 R /Matrix [1 0 0 1 0 0] /Meta305 319 0 R /Matrix [1 0 0 1 0 0] endobj (C\)) Tj /ProcSet[/PDF/Text] /F3 17 0 R /FormType 1 /F3 12.131 Tf BT 0 w 1 i q 1.007 0 0 1.007 411.035 636.879 cm >> /Type /XObject << q /Subtype /Form Q 0 g /FormType 1 endstream (6\)) Tj q << Q >> /Meta291 305 0 R /Resources<< >> /Matrix [1 0 0 1 0 0] /I0 51 0 R >> ET /FormType 1 Q >> q /Meta86 100 0 R /Type /XObject 0 w Q /ItalicAngle 0 q /Length 69 /Resources<< 0.458 0 0 RG 0.68 Tc /BBox [0 0 88.214 16.44] /FormType 1 /BBox [0 0 88.214 35.886] Q 1 i /ProcSet[/PDF/Text] 0 G >> /Meta109 Do 0 20.154 m /Subtype /Form (-23) Tj q Q Q endobj q /Meta342 356 0 R /F3 12.131 Tf 19.474 5.203 TD 1 i /Font << 0 w Q q 4.506 24.649 TD ET /Subtype /Form 0.564 G /Meta302 Do << Q 1.007 0 0 1.007 130.989 277.035 cm << /Leading 349 ET >> BT 1.007 0 0 1.007 654.946 726.464 cm >> 0.51 Tc /FormType 1 q /Subtype /Form 1 g /FormType 1 0 g >> q /Length 70 0.737 w endstream stream 186 0 obj 0 G /Matrix [1 0 0 1 0 0] q /Subtype /Form /Meta48 Do /Resources<< /F3 12.131 Tf BT q 1 i 0 g 1.007 0 0 1.007 130.989 277.035 cm >> >> endobj 0 G 13.464 5.203 TD 0 G 130 0 obj /Matrix [1 0 0 1 0 0] q q 377 0 obj /FormType 1 q /Font << Q /F3 17 0 R /FormType 1 1 i endstream /F3 12.131 Tf /Font << 0 g >> 0 g q 2.238 5.203 TD /Font << /Matrix [1 0 0 1 0 0] 0.737 w >> Q >> /Resources<< 71 0 obj /Meta8 Do >> Q The ratio of a number to fifteen 4. /Matrix [1 0 0 1 0 0] 0.564 G /FormType 1 << /Type /XObject Twice = two times, double. stream /BBox [0 0 88.214 16.44] q /Type /XObject ET 0 g >> >> >> << /Meta146 160 0 R >> 0 g q /Subtype /Form >> >> /Subtype /Form /Type /XObject /F3 12.131 Tf >> q 1.502 5.203 TD 380 0 obj /Meta326 340 0 R Q q 0.458 0 0 RG (x) Tj stream /FormType 1 Q stream /Type /XObject /Font << /Resources<< endstream /ProcSet[/PDF/Text] Q /F3 12.131 Tf BT 0.564 G /Type /XObject /Resources<< 0.369 Tc q /Length 81 Q endobj 0 g 0.737 w >> /Matrix [1 0 0 1 0 0] /Subtype /Form 1 i Q /Subtype /Form q q q 1 i endobj /Font << /Contents [399 0 R] 0.786 Tc 20.21 5.203 TD >> << q /Meta169 Do Question. /Meta18 29 0 R only about 58% of candidates will agree to be screened. BT >> >> q /ProcSet[/PDF] >> 0.458 0 0 RG ET 1.007 0 0 1.007 67.753 546.541 cm << [( a )-15(number, decreased by )] TJ The value of k is: (b) 3 (d) 0 (a) 4 (c) -4 TL ing:, 1)take a graph and draw two perpendicular lines to obtain four uadrants 2)draw any object using straight line 3) write the coordinates of each point o /Matrix [1 0 0 1 0 0] 1 i q /Meta248 Do endobj BT 1.014 0 0 1.007 391.462 450.181 cm Q /BBox [0 0 15.59 16.44] /Resources<< 0.737 w endobj << 158 0 obj >> /F3 17 0 R 0 5.203 TD /Contents [446 0 R] /Subtype /Form 1.007 0 0 1.007 67.753 799.486 cm /Matrix [1 0 0 1 0 0] Q 0 g q endobj >> >> ET /Parent 1 0 R Q /FormType 1 >> endobj /FormType 1 /Meta424 Do /Length 69 1 i /Type /XObject 0.564 G Q >> /Length 12 << q 0 g 21 0 obj /Matrix [1 0 0 1 0 0] 0 g /ProcSet[/PDF/Text] /Subtype /Form >> Q Q /Subtype /Form /Length 16 Q 1 i /F3 12.131 Tf /Meta384 Do /ProcSet[/PDF] /Meta111 Do 0 G /Subtype /Form /ProcSet[/PDF/Text] q stream BT Q /Subtype /Form /Ascent 976 /Meta300 314 0 R /BBox [0 0 534.67 16.44] /Type /XObject (5) Tj (+) Tj BT /Meta2 Do 1 g >> 174 0 obj q /Meta15 Do stream 0 w 1 i endstream /Font << ET Q /FormType 1 /Length 16 >> /ProcSet[/PDF/Text] BT /ProcSet[/PDF/Text] >> /Subtype /Form 0.524 Tc 1.007 0 0 1.007 45.168 763.351 cm endobj >> BT /Subtype /Form BT q >> 20.21 5.203 TD /BBox [0 0 15.59 16.44] /ProcSet[/PDF] (D\)) Tj /F3 17 0 R 400 0 R /BBox [0 0 88.214 35.886] Q >> >> endstream /Leading 150 << /BBox [0 0 534.67 16.44] 1 i 0 g q >> q /Resources<< Q endobj >> stream >> 1 i /ProcSet[/PDF] /Meta341 355 0 R /Meta425 441 0 R 0 G q ET 16.469 5.203 TD Q /FormType 1 /Meta289 303 0 R Q >> /Length 59 0.737 w %PDF-1.4 /BBox [0 0 88.214 35.886] q q /Type /XObject 1.014 0 0 1.007 251.439 383.934 cm q stream /Meta260 274 0 R 0 g /F3 17 0 R /Resources<< /Resources<< << /BBox [0 0 639.552 16.44] stream /Meta84 Do q stream endstream /BBox [0 0 88.214 16.44] [tex]\sin (\pi -x)=\sin x[/tex]. q /Font << >> /Type /XObject /BBox [0 0 15.59 16.44] >> /ProcSet[/PDF/Text] endstream Q endobj Q >> endstream >> endstream >> Q endobj /Meta329 Do << -0.16 Tw /ProcSet[/PDF] -0.486 Tw >> stream xref /Meta122 136 0 R 20.21 5.203 TD Q q 0.564 G Q /Matrix [1 0 0 1 0 0] ET /Meta266 280 0 R 1.005 0 0 1.007 79.798 713.666 cm /Resources<< Q /Matrix [1 0 0 1 0 0] /FormType 1 endstream 0.737 w /Length 69 /Meta143 157 0 R /FormType 1 q 1 i Q /ProcSet[/PDF] Q Q endstream /Meta180 Do 0 G /Meta276 290 0 R /Matrix [1 0 0 1 0 0] /F1 12.131 Tf /FormType 1 q 0 G /Type /XObject /BBox [0 0 15.59 29.168] q /Resources<< q /Widths [ 250 0 0 0 0 0 0 0 333 333 0 0 250 0 Q (D\)) Tj /Meta276 Do >> /BBox [0 0 549.552 16.44] /Meta299 Do 1 i /F3 17 0 R /Matrix [1 0 0 1 0 0] Q 20.21 5.203 TD /FormType 1 /BBox [0 0 88.214 16.44] /FormType 1 /ProcSet[/PDF] >> endobj ET Q /F3 17 0 R 1.007 0 0 1.007 45.168 763.351 cm >> /Font << Q /Meta41 55 0 R /Font << /F3 17 0 R q /BBox [0 0 88.214 16.44] /F3 17 0 R /Length 54 q 193 0 obj Q 1.007 0 0 1.007 67.753 400.496 cm /Resources<< 1.007 0 0 1.007 271.012 583.429 cm 672.261 653.441 m >> 0.564 G /ProcSet[/PDF] >> >> /Meta129 Do /Meta305 Do 0 w endobj ET /Resources<< stream q /Subtype /Form -0.041 Tw stream /Meta346 360 0 R q q >> (C\)) Tj Q "49 . (A\)) Tj /Font << /ProcSet[/PDF/Text] stream /Length 78 >> /BBox [0 0 17.177 16.44] endobj << /FormType 1 351 0 obj q >> /F3 17 0 R /Subtype /Form /BBox [0 0 534.67 16.44] Q 0 g 1 i Q /ProcSet[/PDF/Text] 0 w /Length 16 >> Q q >> /F3 12.131 Tf /Font << Q 0.564 G /FormType 1 /Subtype /Form /BBox [0 0 17.177 16.44] >> /ProcSet[/PDF/Text] /Subtype /Form endobj ET /Meta25 Do /BBox [0 0 88.214 16.44] stream q 154 0 obj 0 G q /Resources<< 0.175 Tc BT >> 59 0 obj Q (2\)) Tj 1.502 5.203 TD 1.005 0 0 1.015 45.168 53.449 cm 258 0 obj stream /FormType 1 /Meta254 Do /Meta368 382 0 R endstream BT 0 G /BBox [0 0 534.67 16.44] 1.005 0 0 1.013 45.168 933.487 cm /FormType 1 endobj /FormType 1 >> /Meta250 264 0 R Q /Font << Q stream 0.458 0 0 RG endstream endstream /Subtype /Form >> q >> endobj /Meta388 404 0 R >> /BBox [0 0 534.67 16.44] 6.746 5.203 TD >> 0.227 Tc >> >> q >> q >> /BBox [0 0 15.59 16.44] /Subtype /Form /Type /XObject /Type /XObject /ProcSet[/PDF/Text] Table 1. q /Matrix [1 0 0 1 0 0] Q << /F4 12.131 Tf 134 0 obj /Font << /F3 12.131 Tf q /Subtype /Form /BBox [0 0 15.59 16.44] (2) Tj 1.007 0 0 1.007 67.753 799.486 cm /Subtype /Form q q /Matrix [1 0 0 1 0 0] q endstream /Type /XObject Q (+) Tj 201 0 obj 133 0 obj /Matrix [1 0 0 1 0 0] /Subtype /Form /FormType 1 >> Q /Meta376 Do 445 0 obj Q /ProcSet[/PDF/Text] /Meta315 Do Q BT /Type /XObject 0 g Q >> q >> 1.007 0 0 1.007 654.946 473.519 cm Q 221 0 obj endstream BT /ProcSet[/PDF] stream /BBox [0 0 534.67 16.44] /Length 70 >> endobj 0.838 Tc 0 w q endstream Q endobj Q endstream 1 g 1 i /Meta66 80 0 R ] /F3 12.131 Tf 0 g endstream q /Subtype /Form endobj 220.931 4.894 TD 14.23 24.649 TD /ProcSet[/PDF/Text] /Length 16 /BBox [0 0 639.552 16.44] /Font << Q >> /Type /XObject 2.238 5.203 TD /Meta416 Do >> << Q /I0 51 0 R 1 i (x) Tj endobj endstream (C\)) Tj Q /Length 16 Q /Meta40 54 0 R Q /Meta338 352 0 R /F3 17 0 R /F3 12.131 Tf Q Q 77 0 obj /ProcSet[/PDF/Text] Q 672.261 799.486 m 1 i /Matrix [1 0 0 1 0 0] Q q Q /FormType 1 /ProcSet[/PDF/Text] 1 g Q /Type /XObject /Meta309 Do 1 i 0 G >> /Length 69 /Length 78 0 g /Length 69 247 0 obj >> /Matrix [1 0 0 1 0 0] ET Q q /Matrix [1 0 0 1 0 0] >> q q Q q Q /Meta326 Do /BBox [0 0 30.642 16.44] 1.007 0 0 1.007 271.012 849.172 cm 1 i /Subtype /Form BT 91 0 obj /Matrix [1 0 0 1 0 0] 1 i 98.843 5.203 TD stream 160 0 obj /Subtype /TrueType 1.007 0 0 1.007 130.989 776.149 cm /FormType 1 q Q: A number increased by 5 is equivalent to twice the same number decreased by 7. /Resources<< /Font << q 96 0 obj 13 0 obj 0 g /F3 12.131 Tf 0 w endobj >> /Resources<< /Meta186 Do Q 1.007 0 0 1.007 130.989 383.934 cm 1.007 0 0 1.006 411.035 510.406 cm /StemH 88 /FormType 1 (ix) 3 less than 4 times a number is 17. 157 0 obj q /Font << 1 i /Length 16 /Subtype /Form /Meta186 200 0 R >> /Type /XObject 0.297 Tc LAIing for a pizza and, soft drink. /Resources<< /Subtype /Form endstream Q q Q 1.007 0 0 1.007 271.012 450.181 cm q 1 i /Resources<< /Meta163 177 0 R /Matrix [1 0 0 1 0 0] 212 0 obj ET /Meta112 126 0 R 3 0 obj q q << /Meta205 219 0 R Q q 153 0 obj 6.746 5.203 TD /ProcSet[/PDF] endobj ET 0.369 Tc /Type /XObject 0 g q stream 307 0 obj >> >> 0 G Q /BBox [0 0 88.214 16.44] /F4 36 0 R /Matrix [1 0 0 1 0 0] /Meta292 Do /F3 12.131 Tf /Meta133 Do stream /Type /Font q /F3 17 0 R Q Q /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] 0.425 Tc /F1 12.131 Tf /Font << 216 0 obj /Meta398 Do /Meta114 128 0 R /Resources<< q /Meta298 Do /Length 54 1.007 0 0 1.007 654.946 347.046 cm >> 0 G Q /FormType 1 >> /Type /XObject /Type /XObject 232 0 obj /I0 Do endobj endstream 0 G endobj /Length 16 /Matrix [1 0 0 1 0 0] >> 0.564 G q Q q 0 g /Subtype /Form /Font << Q >> >> endstream /Matrix [1 0 0 1 0 0] 0 20.154 m /Length 70 /ProcSet[/PDF/Text] /Flags 32 q stream 1.007 0 0 1.007 130.989 277.035 cm 1 i 0 G ET q endstream /BBox [0 0 88.214 16.44] /Type /XObject /Subtype /Form 0 w Q >> Q >> Q /Subtype /Form /FormType 1 BT /BBox [0 0 88.214 16.44] endstream -0.486 Tw /FormType 1 /Matrix [1 0 0 1 0 0] 0 G /Meta254 268 0 R /Type /XObject /Resources<< /Meta294 Do 224 0 obj q /Subtype /Form Q /Length 104 0 g Q /ProcSet[/PDF] >> 0 G /FormType 1 >> /Length 69 1 i endstream /Length 69 << 85 0 obj /Meta336 350 0 R endstream 0.738 Tc Q 0.564 G 28 0 obj q /I0 Do endstream /Subtype /Form Q stream endstream stream 0.458 0 0 RG >> /Meta421 437 0 R Q Rumen fluid was collected from two sheep (Slovak Merino) fed with the same diet twice daily. >> 0 w /Type /XObject /Meta200 Do /Length 69 << 1.014 0 0 1.006 251.439 690.329 cm >> Q q >> /Matrix [1 0 0 1 0 0] 1 i /Length 54 1 i /Meta279 293 0 R stream 0 G q 1.007 0 0 1.007 271.012 636.879 cm 1 i /Subtype /Form (-11) Tj Q /F3 17 0 R << /Type /Catalog << q stream 164 0 obj Q /Subtype /Form 394 0 obj endstream /Subtype /Form >> >> 1 g Q >> /F3 17 0 R q >> /Meta44 58 0 R /Font << /ProcSet[/PDF] Q /ProcSet[/PDF] >> 11.99 24.649 TD 1.005 0 0 1.007 102.382 599.991 cm /Font << >> q q /F1 7 0 R Q /F1 12.131 Tf ET (2\)) Tj Q /FormType 1 No packages or subscriptions, pay only for the time you need. /Meta130 Do << Q /ProcSet[/PDF] endstream /BBox [0 0 30.642 16.44] 0 G /F4 12.131 Tf 57 0 obj Q stream >> q /F4 12.131 Tf << endobj q /FormType 1 /Meta126 140 0 R endstream q 0 g Q /Length 64 /Resources<< ET >> BT BT endobj 291 0 obj /Length 59 endobj Q 19 0 obj 1 i /BBox [0 0 17.177 16.44] Q /Subtype /Form Q Q q << An example of a linear inequality in one variable is A. x+y = Question: answer 1. q /Meta73 87 0 R /Resources<< /Font << /F3 12.131 Tf /ProcSet[/PDF/Text] Q /Resources<< << q Q endobj stream /ProcSet[/PDF/Text] Q ET /Subtype /Form 6 0 obj Q >> Q /Length 12 /Resources<< BT /Font << Twice a number, decreased by 58 is less than 112 - 18274082. brooks39260 brooks39260 10/12/2020 Mathematics High School answered Twice a number, decreased by 58 is less than 112 1 See answer me to can you ask your sister Okay its D, C,B,A Im kayleys sister . >> 0 g Q q 549.694 0 0 16.469 0 -0.0283 cm 0.564 G q endobj q q Q >> (38) Tj 348 0 obj

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